What is the answer to ln(x^2)-ln(5)=4 ?

The answer to ln(x^2)-ln(5)=4 is x=sqrt(5)e^2,x=-sqrt(5)e^2

Solve for x: ln(x^2)-ln(5)=4

The solution is x=sqrt(5)e^2,x=-sqrt(5)e^2

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ln (x^{2}) - ln (5) = 4

x = 5 e^{2}, x = - 5 e^{2}

Solution steps

ln (x^{2}) - ln (5) = 4

Move

ln (5)

to the right side

ln (x^{2}) = 4 + ln (5)

Apply log rules

x^{2} = 5 e^{4}

Solve

x^{2} = 5 e^{4} : x = 5 e^{2}, x = - 5 e^{2}

x = 5 e^{2}, x = - 5 e^{2}

Verify Solutions:

x = 5 e^{2}

True

, x = - 5 e^{2}

True

The solutions are

x = 5 e^{2}, x = - 5 e^{2}

lo g_{2} (x^{2}) = 3

lo g_{x} (36) = 1

ln (x + 1) + ln (x) = 3

ln (x + 1) + ln (x) = 0

x, y = 2 ln (x)

What is the answer to ln(x^2)-ln(5)=4 ?
The answer to ln(x^2)-ln(5)=4 is x=sqrt(5)e^2,x=-sqrt(5)e^2
Solve for x: ln(x^2)-ln(5)=4
The solution is x=sqrt(5)e^2,x=-sqrt(5)e^2