What is the answer to log_{5}(2x+6)=log_{5}(1-x) ?

The answer to log_{5}(2x+6)=log_{5}(1-x) is x=-5/3

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log_{5}(2x+6)=log_{5}(1-x)

lo g_{5} (2 x + 6) = lo g_{5} (1 - x)

x = - \frac{5}{3}

Decimal Notation

x = - 1.66666 \dots

Solution steps

lo g_{5} (2 x + 6) = lo g_{5} (1 - x)

Apply log rules

2 x + 6 = 1 - x

Solve

2 x + 6 = 1 - x : x = - \frac{5}{3}

x = - \frac{5}{3}

Verify Solutions:

x = - \frac{5}{3}

True

The solution is

x = - \frac{5}{3}

1.10395 = 0.6446 ln (x) - 0.5557

3 + ln (x - 4) = 2

lo g_{2} (x) = 1000000000

lo g_{10} (x - 48) = 2 + lo g_{10} (a)

lo g_{3} (3 x + 1) - lo g_{3} (x - 7) = 4

What is the answer to log_{5}(2x+6)=log_{5}(1-x) ?
The answer to log_{5}(2x+6)=log_{5}(1-x) is x=-5/3
Solve for x: log_{5}(2x+6)=log_{5}(1-x)
The solution is x=-5/3