What is the answer to log_{3}(x+1)-log_{3}(x-2)=2 ?

The answer to log_{3}(x+1)-log_{3}(x-2)=2 is x= 19/8

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log_{3}(x+1)-log_{3}(x-2)=2

lo g_{3} (x + 1) - lo g_{3} (x - 2) = 2

x = \frac{19}{8}

Solution steps

lo g_{3} (x + 1) - lo g_{3} (x - 2) = 2

Add

lo g_{3} (x - 2)

to both sides

lo g_{3} (x + 1) - lo g_{3} (x - 2) + lo g_{3} (x - 2) = 2 + lo g_{3} (x - 2)

Simplify

lo g_{3} (x + 1) = 2 + lo g_{3} (x - 2)

Apply log rules

x + 1 = 9 (x - 2)

Solve

x + 1 = 9 (x - 2) : x = \frac{19}{8}

x = \frac{19}{8}

Verify Solutions:

x = \frac{19}{8}

True

The solution is

x = \frac{19}{8}

- 1 = ln (8 x)

ln (5 x) + 4 = ln (3 x + 4)

lo g_{3} (5 x + 3) = 5

x, ln (x + y) = 5

lo g_{10} (x) = 8.79

What is the answer to log_{3}(x+1)-log_{3}(x-2)=2 ?
The answer to log_{3}(x+1)-log_{3}(x-2)=2 is x= 19/8
Solve for x: log_{3}(x+1)-log_{3}(x-2)=2
The solution is x= 19/8