What is the answer to log_{10}(x)+log_{10}(x+2)=9 ?

The answer to log_{10}(x)+log_{10}(x+2)=9 is x=(-2+sqrt(4000000004))/2

Solve for x: log_{10}(x)+log_{10}(x+2)=9

The solution is x=(-2+sqrt(4000000004))/2

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lo g_{10} (x) + lo g_{10} (x + 2) = 9

x = \frac{- 2 + 4000000004}{2}

Solution steps

lo g_{10} (x) + lo g_{10} (x + 2) = 9

Apply log rules

x (x + 2) = 1000000000

Solve

x (x + 2) = 1000000000 : x = \frac{- 2 + 4000000004}{2}, x = \frac{- 2 - 4000000004}{2}

x = \frac{- 2 + 4000000004}{2}, x = \frac{- 2 - 4000000004}{2}

Verify Solutions:

x = \frac{- 2 + 4000000004}{2}

True

, x = \frac{- 2 - 4000000004}{2}

False

The solution is

x = \frac{- 2 + 4000000004}{2}

lo g_{10} (x) + lo g_{10} (x + 2) = 3

ln (x + 3) + ln (x) - ln (2 x) = 3

lo g_{6} (9 x) - lo g_{6} (4) = 2

lo g_{10} (x) = - x + 40

ln (1 - 2 x) = ln (2 - x)

What is the answer to log_{10}(x)+log_{10}(x+2)=9 ?
The answer to log_{10}(x)+log_{10}(x+2)=9 is x=(-2+sqrt(4000000004))/2
Solve for x: log_{10}(x)+log_{10}(x+2)=9
The solution is x=(-2+sqrt(4000000004))/2