What is the answer to log_{x}(2)=128 ?

The answer to log_{x}(2)=128 is x=\sqrt[128]{2}

Solve for x: log_{x}(2)=128

The solution is x=\sqrt[128]{2}

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lo g_{x} (2) = 128

Solution steps

lo g_{x} (2) = 128

Apply log rules

\frac{1}{lo g _{2} ( x )} = 128

Multiply both sides by

lo g_{2} (x)

\frac{1}{lo g _{2} ( x )} lo g_{2} (x) = 128 lo g_{2} (x)

Simplify

1 = 128 lo g_{2} (x)

Switch sides

128 lo g_{2} (x) = 1

Divide both sides by

128

lo g_{2} (x) = \frac{1}{128}

Apply log rules

Verify Solutions:

True

The solution is

x ln (x) - x = 0

- 1 - ln (2 + x) = 0

ln (\frac{1}{x}) = - ln (x)

8 ln (x) = 1

lo g_{10} (x) = 1.709

What is the answer to log_{x}(2)=128 ?
The answer to log_{x}(2)=128 is x=\sqrt[128]{2}
Solve for x: log_{x}(2)=128
The solution is x=\sqrt[128]{2}