What is the answer to log_{6}(x+7)+log_{6}(x+4)=2 ?

The answer to log_{6}(x+7)+log_{6}(x+4)=2 is x=(-11+3sqrt(17))/2

Solve for x: log_{6}(x+7)+log_{6}(x+4)=2

The solution is x=(-11+3sqrt(17))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{6} (x + 7) + lo g_{6} (x + 4) = 2

x = \frac{- 11 + 3 17}{2}

Solution steps

lo g_{6} (x + 7) + lo g_{6} (x + 4) = 2

Apply log rules

(x + 7) (x + 4) = 36

Solve

(x + 7) (x + 4) = 36 : x = \frac{- 11 + 3 17}{2}, x = \frac{- 11 - 3 17}{2}

x = \frac{- 11 + 3 17}{2}, x = \frac{- 11 - 3 17}{2}

Verify Solutions:

x = \frac{- 11 + 3 17}{2}

True

, x = \frac{- 11 - 3 17}{2}

False

The solution is

x = \frac{- 11 + 3 17}{2}

50 = - 22.985 ln (x) + 139.23

lo g_{1000} (a) = \frac{1}{3}

y, ln (y - 47) = 6 t

lo g_{2} (x - 9) + lo g_{2} (x - 2) = 3

lo g_{2} ((x + 4)^{2}) = 6

What is the answer to log_{6}(x+7)+log_{6}(x+4)=2 ?
The answer to log_{6}(x+7)+log_{6}(x+4)=2 is x=(-11+3sqrt(17))/2
Solve for x: log_{6}(x+7)+log_{6}(x+4)=2
The solution is x=(-11+3sqrt(17))/2