What is the answer to log_{2}(x)+log_{2}(3)=4 ?

The answer to log_{2}(x)+log_{2}(3)=4 is x= 16/3

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log_{2}(x)+log_{2}(3)=4

lo g_{2} (x) + lo g_{2} (3) = 4

x = \frac{16}{3}

Decimal Notation

x = 5.33333 \dots

Solution steps

lo g_{2} (x) + lo g_{2} (3) = 4

Move

lo g_{2} (3)

to the right side

lo g_{2} (x) = 4 - lo g_{2} (3)

Apply log rules

x = \frac{16}{3}

Verify Solutions:

x = \frac{16}{3}

True

The solution is

x = \frac{16}{3}

lo g_{2} (x) + lo g_{2} (3) = 3

- ln (x) = ln (2)

8.2 = - lo g_{10} (x)

x, x y + ln (x y) = - 1

ln (\frac{0.43258}{x}) = 0.8915

What is the answer to log_{2}(x)+log_{2}(3)=4 ?
The answer to log_{2}(x)+log_{2}(3)=4 is x= 16/3
Solve for x: log_{2}(x)+log_{2}(3)=4
The solution is x= 16/3