What is the answer to 2log_{3}(x)-log_{27}(x)=10 ?

The answer to 2log_{3}(x)-log_{27}(x)=10 is x=729

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2log_{3}(x)-log_{27}(x)=10

2 lo g_{3} (x) - lo g_{27} (x) = 10

x = 729

Solution steps

2 lo g_{3} (x) - lo g_{27} (x) = 10

Apply log rules

x = 729

Verify Solutions:

x = 729

True

The solution is

x = 729

lo g_{125} (x) = - \frac{1}{3}

y, ln (1 - 2 y) = - 2 t + c

ln (x + 5) - ln (x + 6) = 5

lo g_{2} (x) = 2

- lo g_{10} (x) = 2.24

What is the answer to 2log_{3}(x)-log_{27}(x)=10 ?
The answer to 2log_{3}(x)-log_{27}(x)=10 is x=729
Solve for x: 2log_{3}(x)-log_{27}(x)=10
The solution is x=729