What is the answer to log_{2}(y)+log_{4}(y)=6 ?

The answer to log_{2}(y)+log_{4}(y)=6 is y=16

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log_{2}(y)+log_{4}(y)=6

lo g_{2} (y) + lo g_{4} (y) = 6

y = 16

Solution steps

lo g_{2} (y) + lo g_{4} (y) = 6

Apply log rules

y = 16

Verify Solutions:

y = 16

True

The solution is

y = 16

- 0.3 = lo g_{10} (x)

lo g_{10} (x) = 0.86

3.81 = - lo g_{10} (k)

ln (x) - ln (x - 3) = ln (2)

lo g_{10} (x) = 0.67

What is the answer to log_{2}(y)+log_{4}(y)=6 ?
The answer to log_{2}(y)+log_{4}(y)=6 is y=16
Solve for y: log_{2}(y)+log_{4}(y)=6
The solution is y=16