What is the answer to x^{log_{10}(x^2)+1}=x^3 ?

The answer to x^{log_{10}(x^2)+1}=x^3 is x=10,x=-10

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x^{log_{10}(x^2)+1}=x^3

x^{l o g_{10} (x^{2}) + 1} = x^{3}

x = 10, x = - 10

Solution steps

x^{l o g_{10} (x^{2}) + 1} = x^{3}

Apply exponent rules

lo g_{10} (x^{2}) + 1 = 3

Move

1

to the right side

lo g_{10} (x^{2}) = 2

Apply log rules

x^{2} = 100

Solve

x^{2} = 100 : x = 10, x = - 10

x = 10, x = - 10

Verify Solutions:

x = 10

True

, x = - 10

True

The solutions are

x = 10, x = - 10

lo g_{6} (x) - lo g_{6} (x - 1) = 2

lo g_{2} (x + 4) = 0

lo g_{2} (x + 4) = 4

lo g_{9} (x + 2) - lo g_{9} (x - 6) = 1

x, ln (x^{2} + y) = 0

What is the answer to x^{log_{10}(x^2)+1}=x^3 ?
The answer to x^{log_{10}(x^2)+1}=x^3 is x=10,x=-10
Solve for x: x^{log_{10}(x^2)+1}=x^3
The solution is x=10,x=-10