What is the answer to log_{3}(x^2-2x+3)=1 ?

The answer to log_{3}(x^2-2x+3)=1 is x=2,x=0

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log_{3}(x^2-2x+3)=1

lo g_{3} (x^{2} - 2 x + 3) = 1

x = 2, x = 0

Solution steps

lo g_{3} (x^{2} - 2 x + 3) = 1

Apply log rules

x^{2} - 2 x + 3 = 3

Solve

x^{2} - 2 x + 3 = 3 : x = 2, x = 0

x = 2, x = 0

ln (\frac{1}{x}) = 4

lo g_{10} (x) = 0.58

lo g_{10} (x) 4 = 2

50 = 10 \cdot lo g_{10} (x)

- 2 = lo g_{10} (9 x + 1)

What is the answer to log_{3}(x^2-2x+3)=1 ?
The answer to log_{3}(x^2-2x+3)=1 is x=2,x=0
Solve for x: log_{3}(x^2-2x+3)=1
The solution is x=2,x=0