What is the answer to log_{2-x}(2x^2-1)=2 ?

The answer to log_{2-x}(2x^2-1)=2 is x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2-x}(2x^2-1)=2

lo g_{2 - x} (2 x^{2} - 1) = 2

x = - 5

Solution steps

lo g_{2 - x} (2 x^{2} - 1) = 2

Apply log rules

\frac{ln ( 2 x ^{2} - 1 )}{ln ( 2 - x )} = 2

Multiply both sides by

ln (2 - x)

\frac{ln ( 2 x ^{2} - 1 )}{ln ( 2 - x )} ln (2 - x) = 2 ln (2 - x)

Simplify

ln (2 x^{2} - 1) = 2 ln (2 - x)

Apply log rules

2 x^{2} - 1 = (2 - x)^{2}

Solve

2 x^{2} - 1 = (2 - x)^{2} : x = - 5, x = 1

x = - 5, x = 1

Verify Solutions:

x = - 5

True

, x = 1

False

The solution is

x = - 5

lo g_{e} (x - 2) - 3 lo g_{e} (2) = 2

ln (x + 5) - ln (x - 4) = ln (x)

2 lo g_{10} (x) = lo g_{10} (x) + 3

ln (x) + ln (x + 1) = 2

1.85 = - lo g_{10} (x)

What is the answer to log_{2-x}(2x^2-1)=2 ?
The answer to log_{2-x}(2x^2-1)=2 is x=-5
Solve for x: log_{2-x}(2x^2-1)=2
The solution is x=-5