What is the answer to log_{2}(x^2+x-2)=2 ?

The answer to log_{2}(x^2+x-2)=2 is x=2,x=-3

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log_{2}(x^2+x-2)=2

lo g_{2} (x^{2} + x - 2) = 2

x = 2, x = - 3

Solution steps

lo g_{2} (x^{2} + x - 2) = 2

Apply log rules

x^{2} + x - 2 = 4

Solve

x^{2} + x - 2 = 4 : x = 2, x = - 3

x = 2, x = - 3

0.49 = ln (x)

lo g_{b} (25) = 2

lo g_{10} (x^{2} + 6 x + 10) = 0

(lo g_{8} (x))^{2} = 0

x, ln (x) = t + c

What is the answer to log_{2}(x^2+x-2)=2 ?
The answer to log_{2}(x^2+x-2)=2 is x=2,x=-3
Solve for x: log_{2}(x^2+x-2)=2
The solution is x=2,x=-3