What is the answer to solvefor x,log_{4}(x+y)=3 ?

The answer to solvefor x,log_{4}(x+y)=3 is x=64-y

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solvefor x,log_{4}(x+y)=3

solve for

x, lo g_{4} (x + y) = 3

x = 64 - y

Solution steps

lo g_{4} (x + y) = 3

Apply log rules

x + y = 64

Solve

x + y = 64 : x = 64 - y

x = 64 - y

ln (x) + ln (2 x - 1) = 0

lo g_{4} (x^{2}) = 5 lo g_{4} (x) - 4

2 + lo g_{2} (2 x + 2) = 0

x, y = ln (x^{2})

0.789 = ln (x^{3})

What is the answer to solvefor x,log_{4}(x+y)=3 ?
The answer to solvefor x,log_{4}(x+y)=3 is x=64-y