What are the solutions to the equation 2x^2-5=3x ?

The solutions to the equation 2x^2-5=3x are x= 5/2 ,x=-1

Find the zeros of 2x^2-5=3x

The zeros of 2x^2-5=3x are x= 5/2 ,x=-1

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2 x^{2} - 5 = 3 x

x = \frac{5}{2}, x = - 1

Decimal Notation

x = 2.5, x = - 1

Solution steps

2 x^{2} - 5 = 3 x

Move

3 x

to the left side

2 x^{2} - 5 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 5) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 2}

x = \frac{- ( - 3 ) + 7}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 3 ) - 7}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 1

∣ x - 1 ∣ > 0

3 \geq ∣ q - 4 ∣

420 = 2 (r + 10)

[(a - b)^{2} - c^{2}]

x < \frac{1}{3} or x > - \frac{1}{3}

What are the solutions to the equation 2x^2-5=3x ?
The solutions to the equation 2x^2-5=3x are x= 5/2 ,x=-1
Find the zeros of 2x^2-5=3x
The zeros of 2x^2-5=3x are x= 5/2 ,x=-1