What is the answer to log_{8}(16)+log_{8}(x-2)=2 ?

The answer to log_{8}(16)+log_{8}(x-2)=2 is x=6

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log_{8}(16)+log_{8}(x-2)=2

lo g_{8} (16) + lo g_{8} (x - 2) = 2

x = 6

Solution steps

lo g_{8} (16) + lo g_{8} (x - 2) = 2

Move

lo g_{8} (16)

to the right side

lo g_{8} (x - 2) = 2 - lo g_{8} (16)

Apply log rules

x - 2 = 8^{2 - \frac{4}{3}}

Solve

x - 2 = 8^{2 - \frac{4}{3}} : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

0.7 = - lo g_{10} (x)

x^{l o g_{10} (x)} = 1 0^{6} x

y, ln (y) = 3 + ln (x)

lo g_{10} (2) = lo g_{10} (x)

lo g_{4} (X) = 0

What is the answer to log_{8}(16)+log_{8}(x-2)=2 ?
The answer to log_{8}(16)+log_{8}(x-2)=2 is x=6
Solve for x: log_{8}(16)+log_{8}(x-2)=2
The solution is x=6