What is the answer to -1=-log_{1/2}(x+3)-2 ?

The answer to -1=-log_{1/2}(x+3)-2 is x=-1

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-1=-log_{1/2}(x+3)-2

- 1 = - lo g_{\frac{1}{2}} (x + 3) - 2

x = - 1

Solution steps

- 1 = - lo g_{\frac{1}{2}} (x + 3) - 2

Move

lo g_{\frac{1}{2}} (x + 3)

to the left side

- 1 + lo g_{\frac{1}{2}} (x + 3) = - 2

Move

1

to the right side

lo g_{\frac{1}{2}} (x + 3) = - 1

Apply log rules

x + 3 = 2

Solve

x + 3 = 2 : x = - 1

x = - 1

Verify Solutions:

x = - 1

True

The solution is

x = - 1

lo g_{8} (3 x + 1) = 2

lo g_{8} (16) - lo g_{8} (x - 2) = 2

ln (x + 2) - ln (x) = ln (12)

5 lo g_{2} (x) = 10

lo g_{5} (y) = 2

What is the answer to -1=-log_{1/2}(x+3)-2 ?
The answer to -1=-log_{1/2}(x+3)-2 is x=-1
Solve for x: -1=-log_{1/2}(x+3)-2
The solution is x=-1