What is the answer to -9log_{2}(8-9x)-5=-41 ?

The answer to -9log_{2}(8-9x)-5=-41 is x=-8/9

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-9log_{2}(8-9x)-5=-41

- 9 lo g_{2} (8 - 9 x) - 5 = - 41

x = - \frac{8}{9}

Decimal Notation

x = - 0.88888 \dots

Solution steps

- 9 lo g_{2} (8 - 9 x) - 5 = - 41

Move

5

to the right side

- 9 lo g_{2} (8 - 9 x) = - 36

Divide both sides by

- 9

lo g_{2} (8 - 9 x) = 4

Apply log rules

8 - 9 x = 16

Solve

8 - 9 x = 16 : x = - \frac{8}{9}

x = - \frac{8}{9}

Verify Solutions:

x = - \frac{8}{9}

True

The solution is

x = - \frac{8}{9}

lo g_{5} (x^{2} - 24 x) = 2

lo g_{10} (x) = - 0.26916

lo g_{10} (\frac{1}{x}) = - 6.34

lo g_{x} (5) + lo g_{5} (x) = 2

55000 = 5000 ln (0.3 t + 0.5) + 38000

What is the answer to -9log_{2}(8-9x)-5=-41 ?
The answer to -9log_{2}(8-9x)-5=-41 is x=-8/9
Solve for x: -9log_{2}(8-9x)-5=-41
The solution is x=-8/9