What is the answer to 0=log_{3}(x+3)+2 ?

The answer to 0=log_{3}(x+3)+2 is x=-26/9

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0=log_{3}(x+3)+2

0 = lo g_{3} (x + 3) + 2

x = - \frac{26}{9}

Solution steps

0 = lo g_{3} (x + 3) + 2

Switch sides

lo g_{3} (x + 3) + 2 = 0

Move

2

to the right side

lo g_{3} (x + 3) = - 2

Apply log rules

x + 3 = \frac{1}{9}

Solve

x + 3 = \frac{1}{9} : x = - \frac{26}{9}

x = - \frac{26}{9}

Verify Solutions:

x = - \frac{26}{9}

True

The solution is

x = - \frac{26}{9}

5 lo g_{10} (x) = 3 lo g_{x} (+ 6)

ln (8 ln (x)) = 0

ln (x + 2) + ln (x) = ln (x + 20)

ln (- y + 4) - ln (y + 3) = ln (- 3 y + 1)

lo g_{10} (x) 16 = - 2

What is the answer to 0=log_{3}(x+3)+2 ?
The answer to 0=log_{3}(x+3)+2 is x=-26/9
Solve for x: 0=log_{3}(x+3)+2
The solution is x=-26/9