What is the answer to log_{2}(2x+3)=4 ?

The answer to log_{2}(2x+3)=4 is x= 13/2

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log_{2}(2x+3)=4

lo g_{2} (2 x + 3) = 4

x = \frac{13}{2}

Decimal Notation

x = 6.5

Solution steps

lo g_{2} (2 x + 3) = 4

Apply log rules

2 x + 3 = 16

Solve

2 x + 3 = 16 : x = \frac{13}{2}

x = \frac{13}{2}

x, 0.47 = lo g_{10} (x)

2 lo g_{10} (4 - x) = 2 - x

ln (c x^{8}) = 8 ln (c) + 8 ln (x)

ln (x) + ln (x^{2}) = 3

ln (x) + 7 = 0

What is the answer to log_{2}(2x+3)=4 ?
The answer to log_{2}(2x+3)=4 is x= 13/2
Solve for x: log_{2}(2x+3)=4
The solution is x= 13/2