What is the answer to ln(x+2)+x/(x+2)=0 ?

The answer to ln(x+2)+x/(x+2)=0 is x= 2/(\W_{0)(2e)}-2

Solve for x: ln(x+2)+x/(x+2)=0

The solution is x= 2/(\W_{0)(2e)}-2

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ln (x + 2) + \frac{x}{x + 2} = 0

x = \frac{2}{W _{0} ( 2 e )} - 2

Decimal Notation

x = - 0.54526 \dots

Solution steps

ln (x + 2) + \frac{x}{x + 2} = 0

Move

\frac{x}{x + 2}

to the right side

ln (x + 2) = - \frac{x}{x + 2}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x + 2)} = e^{- \frac{x}{x + 2}}

Simplify

e^{l n (x + 2)} : x + 2

x + 2 = e^{- \frac{x}{x + 2}}

Solve

x + 2 = e^{- \frac{x}{x + 2}} : x = \frac{2}{W _{0} ( 2 e )} - 2

x = \frac{2}{W _{0} ( 2 e )} - 2

Verify Solutions:

x = \frac{2}{W _{0} ( 2 e )} - 2

True

The solution is

x = \frac{2}{W _{0} ( 2 e )} - 2

lo g_{2.718} (a) = 9.06

6 k + ln (1 - 4 k) = 0

ln (x) = ln (5) + ln (8)

lo g_{5} (25 x) + lo g_{x} (5) = 4

lo g_{5} (11 - 6 x) = lo g_{5} (1 - x)

What is the answer to ln(x+2)+x/(x+2)=0 ?
The answer to ln(x+2)+x/(x+2)=0 is x= 2/(\W_{0)(2e)}-2
Solve for x: ln(x+2)+x/(x+2)=0
The solution is x= 2/(\W_{0)(2e)}-2