What is the answer to ln(3x+8)=ln(2x+2)+ln(x-2) ?

The answer to ln(3x+8)=ln(2x+2)+ln(x-2) is x=4

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ln(3x+8)=ln(2x+2)+ln(x-2)

ln (3 x + 8) = ln (2 x + 2) + ln (x - 2)

x = 4

Solution steps

ln (3 x + 8) = ln (2 x + 2) + ln (x - 2)

Apply log rules

3 x + 8 = (2 x + 2) (x - 2)

Solve

3 x + 8 = (2 x + 2) (x - 2) : x = 4, x = - \frac{3}{2}

x = 4, x = - \frac{3}{2}

Verify Solutions:

x = 4

True

, x = - \frac{3}{2}

False

The solution is

x = 4

lo g_{2} (x + 2) - lo g_{2} (x - 2) = 2

lo g_{3} (x + 7) = 3

1.034 + 1.4758 = 1.0445 ln (x)

lo g_{2} (3 x - 2) - lo g_{2} (x - 1) = 4

∣ lo g_{2} (x) ∣ = 3

What is the answer to ln(3x+8)=ln(2x+2)+ln(x-2) ?
The answer to ln(3x+8)=ln(2x+2)+ln(x-2) is x=4
Solve for x: ln(3x+8)=ln(2x+2)+ln(x-2)
The solution is x=4