What is the answer to log_{2}(x^2-9)=4 ?

The answer to log_{2}(x^2-9)=4 is x=5,x=-5

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log_{2}(x^2-9)=4

lo g_{2} (x^{2} - 9) = 4

x = 5, x = - 5

Solution steps

lo g_{2} (x^{2} - 9) = 4

Apply log rules

x^{2} - 9 = 16

Solve

x^{2} - 9 = 16 : x = 5, x = - 5

x = 5, x = - 5

x, lo g_{e} (2 x + 1) = 0

2 lo g_{10} (x - 2) - lo g_{10} (x) = 0

lo g_{10} (x) 64 = 3

5 ln (3 x + 3) + 19 = 59

lo g_{10} (y) = 2.8

What is the answer to log_{2}(x^2-9)=4 ?
The answer to log_{2}(x^2-9)=4 is x=5,x=-5
Solve for x: log_{2}(x^2-9)=4
The solution is x=5,x=-5