What is the answer to 2ln(x)-ln(x^2+x-3)=ln(1) ?

The answer to 2ln(x)-ln(x^2+x-3)=ln(1) is x=3

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2ln(x)-ln(x^2+x-3)=ln(1)

2 ln (x) - ln (x^{2} + x - 3) = ln (1)

x = 3

Solution steps

2 ln (x) - ln (x^{2} + x - 3) = ln (1)

Apply log rules

x^{2} = x^{2} + x - 3

Solve

x^{2} = x^{2} + x - 3 : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

ln (x) = 5.827

0.39 = ln (x)

ln (x) = 2 + c

ln (10 - 0.9 v^{2}) = - 47.642

ln (x + 63) - ln (3 - 2 x) = 6 ln (2)

What is the answer to 2ln(x)-ln(x^2+x-3)=ln(1) ?
The answer to 2ln(x)-ln(x^2+x-3)=ln(1) is x=3
Solve for x: 2ln(x)-ln(x^2+x-3)=ln(1)
The solution is x=3