What are the solutions to the equation 4x^2+6=0 ?

The solutions to the equation 4x^2+6=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i

Find the zeros of 4x^2+6=0

The zeros of 4x^2+6=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 6 = 0

x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

4 x^{2} + 6 = 0

Move

6

to the right side

4 x^{2} = - 6

Divide both sides by

4

x^{2} = - \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{3}{2}, x = - - \frac{3}{2}

- \frac{3}{2} = \frac{3}{2} i

- - \frac{3}{2} = - \frac{3}{2} i

x = \frac{3}{2} i, x = - \frac{3}{2} i

4 x^{2} = 4 x + 5

5 x^{4} + 3 x^{2} - 2

\frac{- 2}{3} + 1

- 2 (x - 5) \geq 6 (x + 7) - 12

Q^{2} + 14 Q + 22 = - Q^{2} - 10 Q + 150

What are the solutions to the equation 4x^2+6=0 ?
The solutions to the equation 4x^2+6=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i
Find the zeros of 4x^2+6=0
The zeros of 4x^2+6=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i