What is the answer to 2-2.12=log_{10}(x) ?

The answer to 2-2.12=log_{10}(x) is x= 1/(10^{0.12)}

Solve for x: 2-2.12=log_{10}(x)

The solution is x= 1/(10^{0.12)}

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2 - 2.12 = lo g_{10} (x)

x = \frac{1}{1 0 ^{0.12}}

Decimal Notation

x = 0.75857 \dots

Solution steps

2 - 2.12 = lo g_{10} (x)

Apply log rules

\frac{1}{1 0 ^{0.12}} = x

Switch sides

x = \frac{1}{1 0 ^{0.12}}

- 35.5 = 10 lo g_{10} (\frac{x}{1})

lo g_{10} (2 + x) = 1

lo g_{4} (5 x + 7) - lo g_{4} (x - 3) = 2

lo g_{10} (x + 2) = 0

lo g_{3} (x) + 2 = lo g_{3} (18)

What is the answer to 2-2.12=log_{10}(x) ?
The answer to 2-2.12=log_{10}(x) is x= 1/(10^{0.12)}
Solve for x: 2-2.12=log_{10}(x)
The solution is x= 1/(10^{0.12)}