What is the answer to 0.027*60=-ln(1-x) ?

The answer to 0.027*60=-ln(1-x) is x=(-1+e^{1.62})/(e^{1.62)}

Solve for x: 0.027*60=-ln(1-x)

The solution is x=(-1+e^{1.62})/(e^{1.62)}

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0.027 \cdot 60 = - ln (1 - x)

x = \frac{- 1 + e ^{1.62}}{e ^{1.62}}

Decimal Notation

x = 0.80210 \dots

Solution steps

0.027 \cdot 60 = - ln (1 - x)

Move

ln (1 - x)

to the left side

1.62 + ln (1 - x) = 0

Move

1.62

to the right side

ln (1 - x) = - 1.62

Apply log rules

1 - x = \frac{1}{e ^{1.62}}

Solve

1 - x = \frac{1}{e ^{1.62}} : x = \frac{- 1 + e ^{1.62}}{e ^{1.62}}

x = \frac{- 1 + e ^{1.62}}{e ^{1.62}}

Verify Solutions:

x = \frac{- 1 + e ^{1.62}}{e ^{1.62}}

True

The solution is

x = \frac{- 1 + e ^{1.62}}{e ^{1.62}}

lo g_{2} (x^{2} + 1) = 1

e^{2} ln (b) = 256

ln (\frac{x}{2}) = 0

- 1 = lo g_{a} (\frac{1}{2})

ln (x) (e) = 0

What is the answer to 0.027*60=-ln(1-x) ?
The answer to 0.027*60=-ln(1-x) is x=(-1+e^{1.62})/(e^{1.62)}
Solve for x: 0.027*60=-ln(1-x)
The solution is x=(-1+e^{1.62})/(e^{1.62)}