What is the answer to log_{12}(1+r/(100))=3 ?

The answer to log_{12}(1+r/(100))=3 is r=172700

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log_{12}(1+r/(100))=3

lo g_{12} (1 + \frac{r}{100}) = 3

r = 172700

Solution steps

lo g_{12} (1 + \frac{r}{100}) = 3

Apply log rules

1 + \frac{r}{100} = 1 2^{3}

Multiply both sides by

100

1 \cdot 100 + \frac{r}{100} \cdot 100 = 1 2^{3} \cdot 100

Simplify

100 + r = 172800

Solve

100 + r = 172800 : r = 172700

r = 172700

Verify Solutions:

r = 172700

True

The solution is

r = 172700

lo g_{5} (x) - lo g_{5} (x - 1) = 1

lo g_{6} (x + 4) = 1 - lo g_{6} (x + 3)

lo g_{4} (x) = lo g_{x} (16)

3 ln (5 x + 1) - 8 = 44

ln (x + 1) = ln (x) + ln (1)

What is the answer to log_{12}(1+r/(100))=3 ?
The answer to log_{12}(1+r/(100))=3 is r=172700
Solve for r: log_{12}(1+r/(100))=3
The solution is r=172700