What is the answer to log_{2}(x^2-1)-2=0 ?

The answer to log_{2}(x^2-1)-2=0 is x=sqrt(5),x=-sqrt(5)

Solve for x: log_{2}(x^2-1)-2=0

The solution is x=sqrt(5),x=-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{2} (x^{2} - 1) - 2 = 0

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

lo g_{2} (x^{2} - 1) - 2 = 0

Move

2

to the right side

lo g_{2} (x^{2} - 1) = 2

Apply log rules

x^{2} - 1 = 4

Solve

x^{2} - 1 = 4 : x = 5, x = - 5

x = 5, x = - 5

Verify Solutions:

x = 5

True

, x = - 5

True

The solutions are

x = 5, x = - 5

lo g_{10} (E) = (11.8 + 1.5 (8))

lo g_{x + 7} (3 x) = 2

lo g_{10} (2 x) - lo g_{10} (x - 4) = 1

ln (x) = 0.24

ln (x) = 0.23

What is the answer to log_{2}(x^2-1)-2=0 ?
The answer to log_{2}(x^2-1)-2=0 is x=sqrt(5),x=-sqrt(5)
Solve for x: log_{2}(x^2-1)-2=0
The solution is x=sqrt(5),x=-sqrt(5)