What is the answer to log_{4}(2x)+log_{4}(x-2)=2 ?

The answer to log_{4}(2x)+log_{4}(x-2)=2 is x=4

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log_{4}(2x)+log_{4}(x-2)=2

lo g_{4} (2 x) + lo g_{4} (x - 2) = 2

x = 4

Solution steps

lo g_{4} (2 x) + lo g_{4} (x - 2) = 2

Apply log rules

2 x (x - 2) = 16

Solve

2 x (x - 2) = 16 : x = 4, x = - 2

x = 4, x = - 2

Verify Solutions:

x = 4

True

, x = - 2

False

The solution is

x = 4

lo g_{10} (5 x) = - 2

- 4 lo g_{8} (3) = lo g_{8} (x)

ln (3 x^{2} + x - 2) = 3 ln (3 x - 2)

lo g_{10} (10 c) = 1

\frac{1}{3} ln (x) = ln (8)

What is the answer to log_{4}(2x)+log_{4}(x-2)=2 ?
The answer to log_{4}(2x)+log_{4}(x-2)=2 is x=4
Solve for x: log_{4}(2x)+log_{4}(x-2)=2
The solution is x=4