What are the solutions to the equation 3x^2-33x-18=0 ?

The solutions to the equation 3x^2-33x-18=0 are x=(11+sqrt(145))/2 ,x=(11-sqrt(145))/2

Find the zeros of 3x^2-33x-18=0

The zeros of 3x^2-33x-18=0 are x=(11+sqrt(145))/2 ,x=(11-sqrt(145))/2

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3 x^{2} - 33 x - 18 = 0

x = \frac{11 + 145}{2}, x = \frac{11 - 145}{2}

Decimal Notation

x = 11.52079 \dots, x = - 0.52079 \dots

Solution steps

3 x^{2} - 33 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 33 ) \pm ( - 33 ) ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

(- 33)^{2} - 4 \cdot 3 (- 18) = 3145

x_{1, 2} = \frac{- ( - 33 ) \pm 3 145}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 33 ) + 3 145}{2 \cdot 3}, x_{2} = \frac{- ( - 33 ) - 3 145}{2 \cdot 3}

x = \frac{- ( - 33 ) + 3 145}{2 \cdot 3} : \frac{11 + 145}{2}

x = \frac{- ( - 33 ) - 3 145}{2 \cdot 3} : \frac{11 - 145}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 145}{2}, x = \frac{11 - 145}{2}

4 x^{2} y - 6 x

\frac{25 !}{19 !}

∣ x + 2 ∣ = 0

- \frac{1}{2} \cdot 2

3 2^{\frac{1}{8}} \cdot 3 2^{\frac{3}{8}}

What are the solutions to the equation 3x^2-33x-18=0 ?
The solutions to the equation 3x^2-33x-18=0 are x=(11+sqrt(145))/2 ,x=(11-sqrt(145))/2
Find the zeros of 3x^2-33x-18=0
The zeros of 3x^2-33x-18=0 are x=(11+sqrt(145))/2 ,x=(11-sqrt(145))/2