What is the answer to 9^{log_{3}(x)}=x-2x^2+4 ?

The answer to 9^{log_{3}(x)}=x-2x^2+4 is x= 4/3

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9^{log_{3}(x)}=x-2x^2+4

9^{l o g_{3} (x)} = x - 2 x^{2} + 4

x = \frac{4}{3}

Decimal Notation

x = 1.33333 \dots

Solution steps

9^{l o g_{3} (x)} = x - 2 x^{2} + 4

Apply log rules

x^{2} = x - 2 x^{2} + 4

Solve

x^{2} = x - 2 x^{2} + 4 : x = - 1, x = \frac{4}{3}

x = - 1, x = \frac{4}{3}

Verify Solutions:

x = - 1

False

, x = \frac{4}{3}

True

The solution is

x = \frac{4}{3}

ln (3 x - 14) = 4

ln (3 x - 14) = 3

3 lo g_{10} (x) = 6

4 lo g_{10} (x) = 4

lo g_{\frac{1}{2}} (x - 2) = - 1

What is the answer to 9^{log_{3}(x)}=x-2x^2+4 ?
The answer to 9^{log_{3}(x)}=x-2x^2+4 is x= 4/3
Solve for x: 9^{log_{3}(x)}=x-2x^2+4
The solution is x= 4/3