What is the answer to log_{9}(x+3)=1+log_{9}(x-2) ?

The answer to log_{9}(x+3)=1+log_{9}(x-2) is x= 21/8

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log_{9}(x+3)=1+log_{9}(x-2)

lo g_{9} (x + 3) = 1 + lo g_{9} (x - 2)

x = \frac{21}{8}

Decimal Notation

x = 2.625

Solution steps

lo g_{9} (x + 3) = 1 + lo g_{9} (x - 2)

Apply log rules

x + 3 = 9 (x - 2)

Solve

x + 3 = 9 (x - 2) : x = \frac{21}{8}

x = \frac{21}{8}

Verify Solutions:

x = \frac{21}{8}

True

The solution is

x = \frac{21}{8}

4 = \frac{n}{lo g _{10} ( n )}

t, ln (t) mb = ln (70) + 0.75 ln (m)

\frac{1}{8} lo g_{2}^{3} (x) = 36

lo g_{10} (4 x + 10) = 3

ln (x) = 3.5

What is the answer to log_{9}(x+3)=1+log_{9}(x-2) ?
The answer to log_{9}(x+3)=1+log_{9}(x-2) is x= 21/8
Solve for x: log_{9}(x+3)=1+log_{9}(x-2)
The solution is x= 21/8