What is the answer to ln(x)+ln(x-6)=2 ?

The answer to ln(x)+ln(x-6)=2 is x=(6+sqrt(36+4e^2))/2

Solve for x: ln(x)+ln(x-6)=2

The solution is x=(6+sqrt(36+4e^2))/2

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ln (x) + ln (x - 6) = 2

x = \frac{6 + 36 + 4 e ^{2}}{2}

Decimal Notation

x = 7.04833 \dots

Solution steps

ln (x) + ln (x - 6) = 2

Apply log rules

x (x - 6) = e^{2}

Solve

x (x - 6) = e^{2} : x = \frac{6 + 36 + 4 e ^{2}}{2}, x = \frac{6 - 36 + 4 e ^{2}}{2}

x = \frac{6 + 36 + 4 e ^{2}}{2}, x = \frac{6 - 36 + 4 e ^{2}}{2}

Verify Solutions:

x = \frac{6 + 36 + 4 e ^{2}}{2}

True

, x = \frac{6 - 36 + 4 e ^{2}}{2}

False

The solution is

x = \frac{6 + 36 + 4 e ^{2}}{2}

ln (x) + ln (x - 6) = 3

ln (20 x - 13) - 13 ln (1) = 0

2 ln (x) - ln (3) = 2

lo g_{10} (x) - lo g_{10} (x - 6) = 4

ln ∣ x ∣ = x - 2

What is the answer to ln(x)+ln(x-6)=2 ?
The answer to ln(x)+ln(x-6)=2 is x=(6+sqrt(36+4e^2))/2
Solve for x: ln(x)+ln(x-6)=2
The solution is x=(6+sqrt(36+4e^2))/2