What is the answer to log_{3}(x)=log_{9}(3x-2) ?

The answer to log_{3}(x)=log_{9}(3x-2) is x=2,x=1

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log_{3}(x)=log_{9}(3x-2)

lo g_{3} (x) = lo g_{9} (3 x - 2)

x = 2, x = 1

Solution steps

lo g_{3} (x) = lo g_{9} (3 x - 2)

Apply log rules

x^{2} = 3 x - 2

Solve

x^{2} = 3 x - 2 : x = 2, x = 1

x = 2, x = 1

Verify Solutions:

x = 2

True

, x = 1

True

The solutions are

x = 2, x = 1

lo g_{a} (49) = \frac{2}{3}

lo g_{x - 3} (2 x^{2} - 11 x + 16) = 2

lo g_{10} (x) (343) = 3

x, 0.22 = ln (x)

lo g_{10} (x^{4}) = \frac{1}{4}

What is the answer to log_{3}(x)=log_{9}(3x-2) ?
The answer to log_{3}(x)=log_{9}(3x-2) is x=2,x=1
Solve for x: log_{3}(x)=log_{9}(3x-2)
The solution is x=2,x=1