What is the answer to 2log_{10}(5x)+log_{10}(x)=2 ?

The answer to 2log_{10}(5x)+log_{10}(x)=2 is x=10^{(2-2log_{10}(5))/3}

Solve for x: 2log_{10}(5x)+log_{10}(x)=2

The solution is x=10^{(2-2log_{10}(5))/3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 lo g_{10} (5 x) + lo g_{10} (x) = 2

x = 1 0^{\frac{2 - 2 l o g _{10} ( 5 )}{3}}

Decimal Notation

x = 1.58740 \dots

Solution steps

2 lo g_{10} (5 x) + lo g_{10} (x) = 2

Apply log rules

x = 1 0^{\frac{2 - 2 l o g _{10} ( 5 )}{3}}

Verify Solutions:

x = 1 0^{\frac{2 - 2 l o g _{10} ( 5 )}{3}}

True

The solution is

x = 1 0^{\frac{2 - 2 l o g _{10} ( 5 )}{3}}

lo g_{10} (\frac{1}{x}) = 1

24 \cdot lo g_{10} (3 x) = 60

10 lo g_{7} (x) = 21

ln (c) = 0

lo g_{10} (\frac{1}{7} x) = - 2

What is the answer to 2log_{10}(5x)+log_{10}(x)=2 ?
The answer to 2log_{10}(5x)+log_{10}(x)=2 is x=10^{(2-2log_{10}(5))/3}
Solve for x: 2log_{10}(5x)+log_{10}(x)=2
The solution is x=10^{(2-2log_{10}(5))/3}