What is the answer to 2log_{2}(x)+7log_{10}(x)-9=0 ?

The answer to 2log_{2}(x)+7log_{10}(x)-9=0 is x=10^{(9log_{10}(2))/(2+7log_{10)(2)}}

Solve for x: 2log_{2}(x)+7log_{10}(x)-9=0

The solution is x=10^{(9log_{10}(2))/(2+7log_{10)(2)}}

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2 lo g_{2} (x) + 7 lo g_{10} (x) - 9 = 0

x = 1 0^{\frac{9 l o g _{10} ( 2 )}{2 + 7 l o g _{10} ( 2 )}}

Decimal Notation

x = 4.56706 \dots

Solution steps

2 lo g_{2} (x) + 7 lo g_{10} (x) - 9 = 0

Apply log rules

x = 1 0^{\frac{9 l o g _{10} ( 2 )}{2 + 7 l o g _{10} ( 2 )}}

Verify Solutions:

x = 1 0^{\frac{9 l o g _{10} ( 2 )}{2 + 7 l o g _{10} ( 2 )}}

True

The solution is

x = 1 0^{\frac{9 l o g _{10} ( 2 )}{2 + 7 l o g _{10} ( 2 )}}

lo g_{10} (10 x^{2}) = 3

lo g_{2} (3 x - 2) + lo g_{2} (x) = 4

lo g_{x + 5} (5 x) = 3

lo g_{2} (x^{(2)} - 6 x) - 6 = - 2

ln (y - 2) = 0

What is the answer to 2log_{2}(x)+7log_{10}(x)-9=0 ?
The answer to 2log_{2}(x)+7log_{10}(x)-9=0 is x=10^{(9log_{10}(2))/(2+7log_{10)(2)}}
Solve for x: 2log_{2}(x)+7log_{10}(x)-9=0
The solution is x=10^{(9log_{10}(2))/(2+7log_{10)(2)}}