What is the answer to log_{10}(x+6)=log_{10}(2x-1) ?

The answer to log_{10}(x+6)=log_{10}(2x-1) is x=7

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log_{10}(x+6)=log_{10}(2x-1)

lo g_{10} (x + 6) = lo g_{10} (2 x - 1)

x = 7

Solution steps

lo g_{10} (x + 6) = lo g_{10} (2 x - 1)

Apply log rules

x + 6 = 2 x - 1

Solve

x + 6 = 2 x - 1 : x = 7

x = 7

Verify Solutions:

x = 7

True

The solution is

x = 7

\frac{1}{2} ln (x) + c = 0

lo g_{4} (\frac{2}{x + 3}) = - 1

lo g_{e} (x) = lo g_{10} (x)

2 (lo g_{8} (x) + lo g_{x} (8)) = 5

ln (x + 6) + ln (x - 2) = 2 ln (x)

What is the answer to log_{10}(x+6)=log_{10}(2x-1) ?
The answer to log_{10}(x+6)=log_{10}(2x-1) is x=7
Solve for x: log_{10}(x+6)=log_{10}(2x-1)
The solution is x=7