What is the answer to log_{2}(x^2+2x-2)=0 ?

The answer to log_{2}(x^2+2x-2)=0 is x=1,x=-3

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log_{2}(x^2+2x-2)=0

lo g_{2} (x^{2} + 2 x - 2) = 0

x = 1, x = - 3

Solution steps

lo g_{2} (x^{2} + 2 x - 2) = 0

Apply log rules

x^{2} + 2 x - 2 = 1

Solve

x^{2} + 2 x - 2 = 1 : x = 1, x = - 3

x = 1, x = - 3

lo g_{4} (2 x + 6) = 2

0.57 = ln (y)

- ln (x + 1) = 1

lo g_{5} (2 x + 5) = lo g_{5} (x + 3)

ln (x) = 7 - x

What is the answer to log_{2}(x^2+2x-2)=0 ?
The answer to log_{2}(x^2+2x-2)=0 is x=1,x=-3
Solve for x: log_{2}(x^2+2x-2)=0
The solution is x=1,x=-3