What is the answer to log_{10}(x)+log_{10}(x+1)=7 ?

The answer to log_{10}(x)+log_{10}(x+1)=7 is x=(-1+sqrt(40000001))/2

Solve for x: log_{10}(x)+log_{10}(x+1)=7

The solution is x=(-1+sqrt(40000001))/2

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lo g_{10} (x) + lo g_{10} (x + 1) = 7

x = \frac{- 1 + 40000001}{2}

Decimal Notation

x = 3161.77769 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x + 1) = 7

Apply log rules

x (x + 1) = 10000000

Solve

x (x + 1) = 10000000 : x = \frac{- 1 + 40000001}{2}, x = \frac{- 1 - 40000001}{2}

x = \frac{- 1 + 40000001}{2}, x = \frac{- 1 - 40000001}{2}

Verify Solutions:

x = \frac{- 1 + 40000001}{2}

True

, x = \frac{- 1 - 40000001}{2}

False

The solution is

x = \frac{- 1 + 40000001}{2}

lo g_{10} (x) + lo g_{10} (x + 1) = 6

lo g_{10} (x) + lo g_{10} (x + 1) = 0

- 0.4 = lo g_{10} (x)

lo g_{10} (x) (4) = \frac{2}{3}

5 ln (3 x - 2) = 15

What is the answer to log_{10}(x)+log_{10}(x+1)=7 ?
The answer to log_{10}(x)+log_{10}(x+1)=7 is x=(-1+sqrt(40000001))/2
Solve for x: log_{10}(x)+log_{10}(x+1)=7
The solution is x=(-1+sqrt(40000001))/2