What is the answer to -2*log_{3}(3-x)+1=0 ?

The answer to -2*log_{3}(3-x)+1=0 is x=3-sqrt(3)

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-2*log_{3}(3-x)+1=0

- 2 \cdot lo g_{3} (3 - x) + 1 = 0

x = 3 - 3

Decimal Notation

x = 1.26794 \dots

Solution steps

- 2 lo g_{3} (3 - x) + 1 = 0

Move

1

to the right side

- 2 lo g_{3} (3 - x) = - 1

Divide both sides by

- 2

lo g_{3} (3 - x) = \frac{1}{2}

Apply log rules

3 - x = 3

Solve

3 - x = 3 : x = 3 - 3

x = 3 - 3

Verify Solutions:

x = 3 - 3

True

The solution is

x = 3 - 3

\frac{ln ( x )}{e} = 0

x, ln (x) = 7

x, ln (x) = 6

x, ln (x) = 3

0 = 3 (ln (5 x) + 1)

What is the answer to -2*log_{3}(3-x)+1=0 ?
The answer to -2*log_{3}(3-x)+1=0 is x=3-sqrt(3)
Solve for x: -2*log_{3}(3-x)+1=0
The solution is x=3-sqrt(3)