What is the answer to ln(4x)+ln(2x)=3 ?

The answer to ln(4x)+ln(2x)=3 is x=e^{(3-3ln(2))/2}

Solve for x: ln(4x)+ln(2x)=3

The solution is x=e^{(3-3ln(2))/2}

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ln (4 x) + ln (2 x) = 3

x = e^{\frac{3 - 3 l n ( 2 )}{2}}

Decimal Notation

x = 1.58451 \dots

Solution steps

ln (4 x) + ln (2 x) = 3

Apply log rules

x = e^{\frac{3 - 3 l n ( 2 )}{2}}

Verify Solutions:

x = e^{\frac{3 - 3 l n ( 2 )}{2}}

True

The solution is

x = e^{\frac{3 - 3 l n ( 2 )}{2}}

8 lo g_{2} (n) = n

lo g_{10} (t) = - 6.016

lo g_{x} (16) = \frac{4}{5}

d = lo g_{2} (\frac{8}{d})

2 ln (x) - (ln (x))^{2} = 0

What is the answer to ln(4x)+ln(2x)=3 ?
The answer to ln(4x)+ln(2x)=3 is x=e^{(3-3ln(2))/2}
Solve for x: ln(4x)+ln(2x)=3
The solution is x=e^{(3-3ln(2))/2}