What is the answer to log_{4}(1+x^2)=-sqrt(0.25) ?

The answer to log_{4}(1+x^2)=-sqrt(0.25) is No Solution for x\in\mathbb{R}

Solve for x: log_{4}(1+x^2)=-sqrt(0.25)

The solution is No Solution for x\in\mathbb{R}

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lo g_{4} (1 + x^{2}) = - 0.25

No Solution for x \in R

Solution steps

lo g_{4} (1 + x^{2}) = - 0.25

Apply log rules

1 + x^{2} = 0.5

Solve

1 + x^{2} = 0.5 :

No Solution for

x \in R

No Solution for x \in R

lo g_{10} (y) = - 138.265

lo g_{2} (\frac{1}{x}) = - 1

ln (x - 2) - ln (8) = 2

lo g_{4} (2 x + 1) - lo g_{2} (1 - x) = 2

lo g_{4} (8) + lo g_{4} (x - 4) = 3

What is the answer to log_{4}(1+x^2)=-sqrt(0.25) ?
The answer to log_{4}(1+x^2)=-sqrt(0.25) is No Solution for x\in\mathbb{R}
Solve for x: log_{4}(1+x^2)=-sqrt(0.25)
The solution is No Solution for x\in\mathbb{R}