What are the solutions to the equation (1+6s)^2=1+30s ?

The solutions to the equation (1+6s)^2=1+30s are s= 1/2 ,s=0

Find the zeros of (1+6s)^2=1+30s

The zeros of (1+6s)^2=1+30s are s= 1/2 ,s=0

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(1 + 6 s)^{2} = 1 + 30 s

s = \frac{1}{2}, s = 0

Solution steps

(1 + 6 s)^{2} = 1 + 30 s

Expand

(1 + 6 s)^{2} : 1 + 12 s + 36 s^{2}

1 + 12 s + 36 s^{2} = 1 + 30 s

Move

30 s

to the left side

36 s^{2} - 18 s + 1 = 1

Move

1

to the left side

36 s^{2} - 18 s = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 36 \cdot 0}{2 \cdot 36}

(- 18)^{2} - 4 \cdot 36 \cdot 0 = 18

s_{1, 2} = \frac{- ( - 18 ) \pm 18}{2 \cdot 36}

Separate the solutions

s_{1} = \frac{- ( - 18 ) + 18}{2 \cdot 36}, s_{2} = \frac{- ( - 18 ) - 18}{2 \cdot 36}

s = \frac{- ( - 18 ) + 18}{2 \cdot 36} : \frac{1}{2}

s = \frac{- ( - 18 ) - 18}{2 \cdot 36} : 0

The solutions to the quadratic equation are:

s = \frac{1}{2}, s = 0

4 x + 6 = 4 (6 x - 3) + 58

- 63 < - 9 c

3 d - 2 \leq - 5 d + 9

2 - ∣ x + 2 ∣ = - 6

0.00001732 = x ((0.084) (0.042))

What are the solutions to the equation (1+6s)^2=1+30s ?
The solutions to the equation (1+6s)^2=1+30s are s= 1/2 ,s=0
Find the zeros of (1+6s)^2=1+30s
The zeros of (1+6s)^2=1+30s are s= 1/2 ,s=0