What is the answer to 37.9=log_{10}(r^{20}) ?

The answer to 37.9=log_{10}(r^{20}) is r=sqrt(10^{3.79)},r=-sqrt(10^{3.79)}

Solve for r: 37.9=log_{10}(r^{20})

The solution is r=sqrt(10^{3.79)},r=-sqrt(10^{3.79)}

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Popular >

37.9 = lo g_{10} (r^{20})

r = 1 0^{3.79}, r = - 1 0^{3.79}

Decimal

r = 78.52356 \dots, r = - 78.52356 \dots

Solution steps

37.9 = lo g_{10} (r^{20})

Apply exponent rule:

a^{2 \cdot n} = (a^{2})^{n}

r^{20} = (r^{2})^{10}

37.9 = lo g_{10} ((r^{2})^{10})

Apply log rules

r^{2} = 1 0^{3.79}

Solve

r^{2} = 1 0^{3.79} : r = 1 0^{3.79}, r = - 1 0^{3.79}

r = 1 0^{3.79}, r = - 1 0^{3.79}

Verify Solutions:

r = 1 0^{3.79}

True

, r = - 1 0^{3.79}

True

The solutions are

r = 1 0^{3.79}, r = - 1 0^{3.79}

ln (4) + ln (x - 3) = - 2

lo g_{10} (x^{2} - 8) = 1

lo g_{3} (x) = 5

ln (2 x) = 2

ln (x - 4) = 2

What is the answer to 37.9=log_{10}(r^{20}) ?
The answer to 37.9=log_{10}(r^{20}) is r=sqrt(10^{3.79)},r=-sqrt(10^{3.79)}
Solve for r: 37.9=log_{10}(r^{20})
The solution is r=sqrt(10^{3.79)},r=-sqrt(10^{3.79)}