What is the answer to log_{6}(x^6)=1 ?

The answer to log_{6}(x^6)=1 is x=sqrt(\sqrt[3]{6)},x=-sqrt(\sqrt[3]{6)}

Solve for x: log_{6}(x^6)=1

The solution is x=sqrt(\sqrt[3]{6)},x=-sqrt(\sqrt[3]{6)}

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lo g_{6} (x^{6}) = 1

Decimal Notation

x = 1.34800 \dots, x = - 1.34800 \dots

Solution steps

lo g_{6} (x^{6}) = 1

Apply exponent rule:

a^{2 \cdot n} = (a^{2})^{n}

x^{6} = (x^{2})^{3}

lo g_{6} ((x^{2})^{3}) = 1

Apply log rules

Solve

Verify Solutions:

True

The solutions are

5 lo g_{10} (x - 13) = 1

lo g_{10} (lo g_{10} (x)) = 1.01

lo g_{10} (x) = 17

lo g_{10} (x) = 19

lo g_{3} (9 x) = 5

What is the answer to log_{6}(x^6)=1 ?
The answer to log_{6}(x^6)=1 is x=sqrt(\sqrt[3]{6)},x=-sqrt(\sqrt[3]{6)}
Solve for x: log_{6}(x^6)=1
The solution is x=sqrt(\sqrt[3]{6)},x=-sqrt(\sqrt[3]{6)}