What is the answer to log_{10}((1+6x)/7)=1 ?

The answer to log_{10}((1+6x)/7)=1 is x= 23/2

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log_{10}((1+6x)/7)=1

lo g_{10} (\frac{1 + 6 x}{7}) = 1

x = \frac{23}{2}

Decimal Notation

x = 11.5

Solution steps

lo g_{10} (\frac{1 + 6 x}{7}) = 1

Apply log rules

\frac{1 + 6 x}{7} = 1 0^{1}

Multiply both sides by

7

\frac{1 + 6 x}{7} \cdot 7 = 1 0^{1} \cdot 7

Simplify

1 + 6 x = 70

Solve

1 + 6 x = 70 : x = \frac{23}{2}

x = \frac{23}{2}

Verify Solutions:

x = \frac{23}{2}

True

The solution is

x = \frac{23}{2}

0.8 = lo g_{10} (\frac{x}{140})

lo g_{5} (x - 3) = - 2

lo g_{10} (x) 9 = - 2

lo g_{5} (x - 1) = lo g_{5} (3)

x, 5.812 = ln (x)

What is the answer to log_{10}((1+6x)/7)=1 ?
The answer to log_{10}((1+6x)/7)=1 is x= 23/2
Solve for x: log_{10}((1+6x)/7)=1
The solution is x= 23/2