What is the answer to log_{2}(9)+log_{2}(x+3)=3 ?

The answer to log_{2}(9)+log_{2}(x+3)=3 is x=-19/9

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log_{2}(9)+log_{2}(x+3)=3

lo g_{2} (9) + lo g_{2} (x + 3) = 3

x = - \frac{19}{9}

Decimal Notation

x = - 2.11111 \dots

Solution steps

lo g_{2} (9) + lo g_{2} (x + 3) = 3

Move

lo g_{2} (9)

to the right side

lo g_{2} (x + 3) = 3 - lo g_{2} (9)

Apply log rules

x + 3 = \frac{8}{9}

Solve

x + 3 = \frac{8}{9} : x = - \frac{19}{9}

x = - \frac{19}{9}

Verify Solutions:

x = - \frac{19}{9}

True

The solution is

x = - \frac{19}{9}

lo g_{10} (c) = 0.5

x, ln (y) = - 2 ln (x) + c

12 = - 10 lo g_{10} ((1 - x)^{2})

ln (γ) = ln (4 + e^{2^{β}}) + ω

lo g_{7} (\frac{1}{x}) = - 3

What is the answer to log_{2}(9)+log_{2}(x+3)=3 ?
The answer to log_{2}(9)+log_{2}(x+3)=3 is x=-19/9
Solve for x: log_{2}(9)+log_{2}(x+3)=3
The solution is x=-19/9