What is the answer to log_{2}(x+3)+log_{2}(x-5)=0 ?

The answer to log_{2}(x+3)+log_{2}(x-5)=0 is x=1+sqrt(17)

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log_{2}(x+3)+log_{2}(x-5)=0

lo g_{2} (x + 3) + lo g_{2} (x - 5) = 0

x = 1 + 17

Decimal Notation

x = 5.12310 \dots

Solution steps

lo g_{2} (x + 3) + lo g_{2} (x - 5) = 0

Apply log rules

(x + 3) (x - 5) = 1

Solve

(x + 3) (x - 5) = 1 : x = 1 + 17, x = 1 - 17

x = 1 + 17, x = 1 - 17

Verify Solutions:

x = 1 + 17

True

, x = 1 - 17

False

The solution is

x = 1 + 17

lo g_{5} (x + 6) = - lo g_{5} (x + 2) + 1

lo g_{4} (x + 11) = 2

20 \cdot lo g_{10} (x) = 0

ln (x + e) = 3

20 \cdot lo g_{10} (x) = 7

What is the answer to log_{2}(x+3)+log_{2}(x-5)=0 ?
The answer to log_{2}(x+3)+log_{2}(x-5)=0 is x=1+sqrt(17)
Solve for x: log_{2}(x+3)+log_{2}(x-5)=0
The solution is x=1+sqrt(17)