What is the answer to 1.02=log_{10}(x) ?

The answer to 1.02=log_{10}(x) is x=10^{1.02}

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1.02=log_{10}(x)

1.02 = lo g_{10} (x)

x = 1 0^{1.02}

Decimal Notation

x = 10.47128 \dots

Solution steps

1.02 = lo g_{10} (x)

Apply log rules

1 0^{1.02} = x

Switch sides

x = 1 0^{1.02}

6 lo g_{3} (x - 3) = - 24

2 - 2 ln (x) = 2.5

0 = \frac{ln ( x )}{x}

ln (x - 8) - ln (2) = ln (x)

lo g_{3} (7 x + 1) = 3

What is the answer to 1.02=log_{10}(x) ?
The answer to 1.02=log_{10}(x) is x=10^{1.02}
Solve for x: 1.02=log_{10}(x)
The solution is x=10^{1.02}